y+7=y^2-(y+1)(y-3)

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Solution for y+7=y^2-(y+1)(y-3) equation: 



y+7=y^2-(y+1)(y-3)

We move all terms to the left:

y+7-(y^2-(y+1)(y-3))=0

We multiply parentheses ..

-(y^2-(+y^2-3y+y-3))+y+7=0



We calculate terms in parentheses: -(y^2-(+y^2-3y+y-3)), so:

y^2-(+y^2-3y+y-3)

We get rid of parentheses

y^2-y^2+3y-y+3

We add all the numbers together, and all the variables

2y+3

Back to the equation:

-(2y+3)



We add all the numbers together, and all the variables

y-(2y+3)+7=0

We get rid of parentheses

y-2y-3+7=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4

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